PCl 5 ⇌ PCl 3 + Cl 2 K c = 1 . 844 3 . 0 moles of PCl 5 is introduced in a 1 L closed reaction vessel at 380 K . The number of moles of PCl 5 at equilibrium is — × 10 - 3 (Round off to the Nearest Integer)

Question

PCl 5 &#8652; PCl 3 + Cl 2 K c = 1 . 844 3 . 0 moles of PCl 5 is introduced in a 1 L closed reaction vessel at 380 K . The number of moles of PCl 5 at equilibrium is &#8212; &#215; 10 - 3 (Round off to the Nearest Integer)

Quantrex Academy · Accepted Answer

Correct answer: 0

&#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; PCl 5 ( &#160; g ) &#8652; PCl 3 ( &#160; g ) + Cl 2 ( &#160; g ) &#160; &#160; &#160; &#160; K c = 1 . 844 t = 0 &#160; &#160; &#160; &#160; &#160; 3 &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; 0 &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; 0 t = t eq &#160; &#160; &#160; 3 - x &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160;

PCl 5 ⇌ PCl 3 + Cl 2 K c = 1 . 844 3 . 0 moles of PCl 5 is introduced in a 1 L closed reaction vessel at 380 K . The number of moles of PCl 5 at equilibrium is — × 10 - 3 (Round off to the Nearest Integer)

Correct answer

Step-by-step solution

More from Chemical Equilibrium

PCl 5 &#8652; PCl 3 + Cl 2 K c = 1 . 844 3 . 0 moles of PCl 5 is introduced in a 1 L closed reaction vessel at 380 K . The number of moles of PCl 5 at equilibrium is &#8212; &#215; 10 - 3 (Round off to the Nearest Integer)

Correct answer

Step-by-step solution

More from Chemical Equilibrium

PCl 5 ⇌ PCl 3 + Cl 2 K c = 1 . 844 3 . 0 moles of PCl 5 is introduced in a 1 L closed reaction vessel at 380 K . The number of moles of PCl 5 at equilibrium is — × 10 - 3 (Round off to the Nearest Integer)