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JEE Main 202127 JulyEvening Shift

Exam: JEE Main
Year: 2021
Date: 27 July
Shift: Evening Shift
Subject: Chemistry
Chapter: Chemical Equilibrium

JEE Main 2021 · 27 July · Evening Shift · Chemistry · Chemical Equilibrium

The equilibrium constant for the reaction A ( s ) ⇌ M ( s ) +...

The equilibrium constant for the reaction

A ( s ) ⇌ M ( s ) + \dfrac{1}{2}{O}_{2} ( g )

is

{K}_{p} = 4 .

At equilibrium, the partial pressure of

{O}_{2}

is _____ atm. (Round off to the nearest integer)

Correct answer

0

Step-by-step solution

${K}_{p} = {P}_{{O}_{2}}^{1 / 2} = 4$

$∴ {P}_{{O}_{2}} = 16atm$

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