JEE Main202120 Jul 2021Morning ShiftChemistryChemical EquilibriumActual
2 SO 2 ( g ) + O 2 ( g ) ⇌ 2 SO 3 ( g ) In an equilibrium mixture, the partial pressures are P SO 3 = 43 kPa ; P O 2 = 530 Pa and P SO 2 = 45 kPa . The equilibrium constant K P = _ _ _ _ _ × 10 - 2 . (Nearest integer)
Correct answer
0
Step-by-step solution
2 SO 2 (   g ) + O 2 (   g ) = 2 SO 3 (   g ) K P = pSO 3 (   g ) 2 pSO 2 g 2 × pO 2 (   g ) = 43 × 43 45 × 45 × 0 . 530   = 172 . 28 × 10 - 2   kPa - 1 ≃ 172   ×   10 - 2 Ans is 172