JEE Main202117 Mar 2021Evening ShiftChemistryChemical EquilibriumActual
Consider the reaction N 2 O 4 (   g ) ⇌ 2 NO 2 (   g ) The temperature at which K C = 20 . 4 and K P = 600 . 1 , is ______ K . (Round off to the Nearest Integer). [Assume all gases are ideal and R = 0 . 0831   L bar K - 1   mol - 1
Correct answer
0
Step-by-step solution
N 2 O 4 (   g ) ⇌ 2 NO 2 (   g ) ; Δn g = 2 - 1 = 1 Now, K p = K c · ( RT ) ∆ n g or, 600 . 1 = 20 . 4 × ( 0 . 0831 × T ) 1 ∴ T = 353 . 99   K = 354   K