A homogeneous ideal gaseous reaction AB _ 2(g) ⇌ A _ (g) + 2 B _...

A homogeneous ideal gaseous reaction

{AB}_{2\left(g\right)} ⇌ {A}_{\left(g\right)} + 2{B}_{\left(g\right)}

is carried out in a

25litre

flask at

27 ° C

. The initial amount of

{AB}_{2}

was

1

mole and the equilibrium pressure was

1 . 9atm

. The value of

{K}_{p}

x \times {10}^{- 2}

. The value of

x

is (Integer answer) \left[R = 0 . 08206{dm}^{3}atm{K}^{- 1}{mol}^{- 1}\right]

Correct answer

Step-by-step solution

$\begin{array}{ll}{AB}_{2} \\ 1 \\ 1 - \alpha \\ 0 . 535\end{array}$ $\begin{array}{ll}⇌\end{array}$ $\begin{array}{ll}A \\ \alpha \\ 0 . 465\end{array}$ $\begin{array}{ll}+ & 2B \\ 2\alpha \\ 0 . 9\end{array}$ $$ 1 . 9 \times 25 = {n}_{T} \times 0 . 08206 \times 300 $$ {n}_{T} = 1 . 93 = 1 + 2\alpha $$ \alpha = 0 . 465 $$ Kp = \dfrac{\left(\dfrac{0 . 465}{1 . 93} \times 19\right){\left(\dfrac{0 . 93}{1 . 93} \times 1 . 9\right)}^{2}}{\left(\dfrac{0 . 535}{1 . 93} \times 1 . 9\right)} $$ ≃ 73 \times {10}^{- 2}{atm}^{2}$

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