JEE Main202124 Feb 2021Morning ShiftChemistryChemical EquilibriumActual
The stepwise formation of Cu NH 3 4 2 + is given below: Cu 2 + + NH 3 ⇌ K 1 Cu NH 3 2 + Cu NH 3 2 + + NH 3 ⇌ K 2 Cu NH 3 2 2 + Cu NH 3 2 2 + + NH 3 ⇌ K 3 Cu NH 3 3 2 + Cu NH 3 3 2 + + NH 3 ⇌ K 4 Cu NH 3 4 2 + The value of stability constants K 1 ,   K 2 ,   K 3 and K 4 are 10 4 ,   1 . 58 × 10 3 ,   5 × 10 2 and 10 2 respectively. The overall equilibrium constants
Correct answer
0
Step-by-step solution
Cu 2 + + NH 3 ⇌ K 1 Cu NH 3 2 + Cu NH 3 2 + + NH 3 ⇌ K 2 Cu NH 3 2 2 + Cu NH 3 2 2 + + NH 3 ⇌ K 3 Cu NH 3 3 2 + Cu NH 3 3 2 + + NH 3 ⇌ K 4 Cu NH 3 4 2 + Cu 2 + + 4 NH 3 ⇌ K Cu NH 3 4 2 + So, K = K 1 × K 2 × K 3 × K 4 = 10 4 × 1 .58 × 10 3 × 5 × 10 2 × 10 2 K = 7 .9 × 10 11 Where K → Equilibrium constant for formation of Cu NH 3 4 2 + So equilibrium constant K ' for dissociation  of  Cu NH 3 4 2 +  is  1   K