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JEE Main 20205 SeptemberEvening Shift

Exam: JEE Main
Year: 2020
Date: 5 September
Shift: Evening Shift
Subject: Chemistry
Chapter: Chemical Equilibrium

JEE Main 2020 · 5 September · Evening Shift · Chemistry · Chemical Equilibrium

For a reaction X + Y = 2Z, 1 . 0mol of X, 1 . 5mol of Y and 0 ....

For a reaction

X + Y = 2Z, 1 . 0mol

of

X, 1 . 5mol

of

Y

and

0 . 5mol

of

Z

were taken in a

1L

vessel and allowed to react. At equilibrium, the concentration of

Z

was

1 . 0{molL}^{- 1}

. the equilibrium constant of the reaction is

\ldots \ldots \ldots \ldots \dfrac{x}{15} .

The value of x is

\ldots \ldots .

For a reaction X + Y = 2Z, 1 . 0mol of X, 1 . 5mol of Y and 0 . 5mol of Z were taken in a 1L vessel and allowed to

Correct answer

0

Step-by-step solution

$x + y = 2z$

$t = 01mol$ $1 . 5mol0 . 5mol$

Since moles of $Z$ are increased at equilibrium therefore reaction goes in forward direction to attain the
equilibrium.

For a reaction X + Y = 2Z, 1 . 0mol of X, 1 . 5mol of Y and 0 . 5mol of Z were taken in a 1L vessel and allowed to

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