For a reaction X + Y = 2 Z , 1 . 0 mol of X , 1 . 5 mol of Y and 0 . 5 mol of Z were taken in a 1 L vessel and allowed to react. At equilibrium, the concentration of Z was 1 . 0 molL - 1 . the equilibrium constant of the reaction is …

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For a reaction X + Y = 2 Z , 1 . 0 mol of X , 1 . 5 mol of Y and 0 . 5 mol of Z were taken in a 1 L vessel and allowed to react. At equilibrium, the concentration of Z was 1 . 0 molL - 1 . the equilibrium constant of the reaction is &#8230; &#8230; &#8230; &#8230; x 15 . The value of x is &#8230; &#8230; .

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Correct answer: 0

x &#160; &#160; &#160; + &#160; &#160; &#160; y = &#160; &#160; &#160; 2 &#160; z t = 0 &#160; 1 mol 1 . 5 mol &#160;&#160; 0 . 5 mol Since moles of Z are increased at equilibrium therefore reaction goes in forward direction to attain the equilibrium.

For a reaction X + Y = 2 Z , 1 . 0 mol of X , 1 . 5 mol of Y and 0 . 5 mol of Z were taken in a 1 L vessel and allowed to react. At equilibrium, the concentration of Z was 1 . 0 molL - 1 . the equilibrium constant of the reaction is … … … … x 15 . The value of x is … … .

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