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JEE Main 20206 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2020 · 6 September · Morning Shift · Chemistry · Chemical Equilibrium

For the reaction Fe _ 2 N(s) + (3)/(2) H _ 2 (g) ⇌ 2Fe(s) + NH _ 3...

For the reaction
${Fe}_{2}N\left(s\right) + \dfrac{3}{2}{H}_{2}\left(g\right) ⇌ 2Fe\left(s\right) + {NH}_{3}\left(g\right)

Options

  1. AKc=Kp(RT){K}_{c} = {K}_{p} ( RT )
  2. BKc=Kp(RT)−1/2{K}_{c} = {K}_{p} ( RT{)}^{- 1 / 2}
  3. CKc=Kp(RT)1/2{K}_{c} = {K}_{p} ( RT{)}^{1 / 2}
  4. DKc=Kp(RT)3/2{K}_{c} = {K}_{p} ( RT{)}^{3 / 2}

Correct answer

C. Kc=Kp(RT)1/2{K}_{c} = {K}_{p} ( RT{)}^{1 / 2}

Step-by-step solution

KP=KC(RT)Δng{K}_{P} = {K}_{C}{\left(RT\right)}^{\Delta ng}

KP=KC(RT)1−32{K}_{P} = {K}_{C}{\left(RT\right)}^{1 - \dfrac{3}{2}}

KC=KP(RT)12{K}_{C} = {K}_{P}\left(RT\right)\dfrac{1}{2}

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