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JEE Main 20163 April
Exam
JEE Main
Year
2016
Date
3 April
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2016 · 3 April · Chemistry · Chemical Equilibrium

The equilibrium constant at 298K for a reaction A + B ⇌ C + D is...

The equilibrium constant at 298K298K for a reaction A+B⇌C+DA + B ⇌ C + D is 100100. If the initial concentration of all the four species were1M1M each, then the equilibrium concentration of DD (in mol L−1{L}^{- 1}) will be:

Options

  1. A1.8181 . 818
  2. B1.1821 . 182
  3. C0.1820 . 182
  4. D0.8180 . 818

Correct answer

A. 1.8181 . 818

Step-by-step solution

K at 298K298K for the reaction
A+B⇌C+DA + B ⇌ C + D is 100100.

Given: The initial concentration of all four species is 1M1M.
{A+B⇌C+Dt=01111atequilbrium1−x1−x1+x1+x\begin{cases}A & + & B & ⇌ & C & + & D \\ t = 0 & 1 & 1 & 1 & 1 \\ atequilbrium & 1 - x & 1 - x & 1 + x & 1 + x\end{cases}

K=(1+x)(1+x)(1−x)(1−x)=100K = \dfrac{\left(1 + x\right)\left(1 + x\right)}{\left(1 - x\right)\left(1 - x\right)} = 100
⇒(1+x)1−x=10⇒ \dfrac{\left(1 + x\right)}{1 - x} = 10
⇒x=911=0.818⇒ x = \dfrac{9}{11} = 0.818
⇒[D]=1+x=1+0.818=1.818⇒ \left[D\right] = 1 + x = 1 + 0.818 = 1.818
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