Gaseous N 2 O 4 dissociates into gaseous N O 2 according to the reaction N 2 O 4 g ⇌ 2 N O 2 g At 300 K and 1 atm pressure, the degree of dissociation of N 2 O 4 is 0 . 2 . If one mole of N 2 O 4 gas is contained in a vessel, then the density of the equilibrium mixture is :

Step-by-step solution

N 2 O 4 ⇌ 2 N O 2 1 - α 2 α Total moles at equilibrium = 1 - α + 2 α = 1 + α = 1.2 M a v g for equilibrium mixture = 0.8 × 92 + 0.4 × 46 1.2    =   76 . 67   g / mol d a v e r a g e   = P M a v g R T = 1 × 76.67 0.082 × 300 = 76.67 24.6 = 3.11   g L - 1