JEE Main2015ChemistryChemical EquilibriumActual
The standard Gibbs energy change at 300 K for the reaction 2 A ⇌ B + C is 2494.2 J. At a given time, the composition of the reaction mixture is A = 1 2 , B = 2 and C = 1 2 . The reaction proceeds in the: [ R = 8.314 J / K - m o l , e = 2.718 ] Given antilog (-0.44)=0.36
Options
- AReverse direction because Q < K C
- BForward direction because Q > K C
- CReverse direction because Q > K C
- DForward direction because Q < K C
Correct answer
C. Reverse direction because Q > K C
Step-by-step solution
Δ G ∘ = - RT ln K C 2494.2 = - 8.314 × 300 ln K C 2494.2 = - 8.314 × 300 × 2.303 log K C - 2494.2 2.303 × 300 × 8.314 = - 0.44 = log K C log K C = - 0.44 K C = 0.36 Q = [ B ] [ C ] [ A ] 2 = 2 × 1 2 1 2 2 = 4 Q > K C , reaction will shift in reverse direction.