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JEE Main 20146 April
Exam
JEE Main
Year
2014
Date
6 April
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2014 · 6 April · Chemistry · Chemical Equilibrium

For the reaction SO _ 2 (g) + (1)/(2) O _ 2 (g) ⇌ SO _ 3 (g) , if K...

For the reaction SO2(g)+12O2(g)⇌SO3(g){\text{SO}}_{2} \left(\text{g}\right) + \dfrac{1}{2} {\text{O}}_{2} \left(\text{g}\right) ⇌ {\text{SO}}_{3} \left(\text{g}\right) , if KP=KC(RT)x{\text{K}}_{\text{P}} = {\text{K}}_{\text{C}} {\left(\text{RT}\right)}^{x} where the symbols have usual meaning then the value of xx is:
(assuming ideality)

Options

  1. A−1- 1
  2. B−12- \dfrac{1}{2}
  3. C12\dfrac{1}{2}
  4. D11

Correct answer

B. −12- \dfrac{1}{2}

Step-by-step solution

KP=KC(RT)Δng{\text{K}}_{\text{P}} = {\text{K}}_{\text{C}} {\left(\text{RT}\right)}^{\Delta {\text{n}}_{\text{g}}}

SO2(g)+12O2(g)⇌SO3(g){\text{SO}}_{2} ( \text{g} ) + \dfrac{1}{2} {\text{O}}_{2} ( \text{g} ) ⇌ {\text{SO}}_{3} \left(\text{g}\right)

\Deltang=1−(1+12)=−12\text{\Delta}{\text{n}}_{\text{g}} = 1 - ( 1 + \dfrac{1}{2} ) = - \dfrac{1}{2}
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