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JEE Main2012ChemistryChemical EquilibriumActual

8 ~mol of A B₃( ~g ) are introduced into a 1.0 dm ^3 vessel. If it dissociates as 2 AB ₃(g) A₂(g)+3 B₂(g) . At equilibrium, 2 ~mol of A₂ are found to be present. The equilibrium constant of this reaction is

Options

  1. A2
  2. B3
  3. C27
  4. D36

Correct answer

C. 27

Step-by-step solution

2 A B₃(g) A₂(g)+3 B₂(g) at t=0 8 0 0 at eq. (8-2 2) 2 3 2=4 2 6 now K_C= [A₂ ] [B₂ ]^3 [A B₃ ]^2 = 2 / 1 [6 / 1]^3 [4 / 1]^2 =27

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