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JEE Main 201212 MayOnline
Exam
JEE Main
Year
2012
Date
12 May
Mode
Online
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2012 · 12 May · Online · Chemistry · Chemical Equilibrium

8 ~mol of A B_3(~g) are introduced into a 1.0 dm^3 vessel. If it...

8 mol8 \mathrm{~mol} of AB3( g)A B_3(\mathrm{~g}) are introduced into a 1.0dm31.0 \mathrm{dm}^3 vessel. If it dissociates as 2AB3(g)⇌A2(g)+3B2(g)2 \mathrm{AB}_3(g) \rightleftharpoons A_2(g)+3 B_2(g). At equilibrium, 2 mol2 \mathrm{~mol} of A2A_2 are found to be present. The equilibrium constant of this reaction is

Options

  1. A2
  2. B3
  3. C27
  4. D36

Correct answer

C. 27

Step-by-step solution

2AB3(g)⇋A2(g)+3B2(g)2 A B_3(g) \leftrightharpoons A_2(g)+3 B_2(g) at t=0800t=0 \quad 8 \quad 0 \quad 0 at eq. (8−2×2)23×2(8-2 \times 2) \quad 2 \quad 3 \times 2 =426=4 \quad 2 \quad 6 now KC=[A2][B2]3[AB3]2=2/1×[6/1]3[4/1]2=27K_C=\frac{\left[A_2\right]\left[B_2\right]^3}{\left[A B_3\right]^2}=\frac{2 / 1 \times[6 / 1]^3}{[4 / 1]^2}=27
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