For the following three reactions a, b and c , equilibrium constants are given: a. CO(g)+H_2 O(g) leftharpoons CO_2(~g)+H_2(~g) ; K_1 b. CH_4(~g)+H_2 O(g) leftharpoons CO(g)+3 H_2(~g) ; K_2 c. CH_4(~g)+2 H_2 O(g)

Correct answer: C. K_3=K_1 ~K_2 Equation (c) = equation (a) + equation (b) Thus K_3=K_1 · K_2

JEE Main 2008

JEE Main 2008 · Chemistry · Chemical Equilibrium

For the following three reactions a, b and c , equilibrium...

For the following three reactions

a, b

and

c

, equilibrium constants are given: a.

\mathrm{CO}(\mathrm{g})+\mathrm{H}_2 \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}_2(\mathrm{~g})+\mathrm{H}_2(\mathrm{~g}) ; \quad \mathrm{K}_1

\mathrm{CH}_4(\mathrm{~g})+\mathrm{H}_2 \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+3 \mathrm{H}_2(\mathrm{~g}) ; \quad \mathrm{K}_2

\mathrm{CH}_4(\mathrm{~g})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}_2(\mathrm{~g})+4 \mathrm{H}_2(\mathrm{~g}) ; \mathrm{K}_3

Which of the following relations is correct?

C. $\mathrm{K}_3=\mathrm{K}_1 \mathrm{~K}_2$

Equation (c) = equation (a) + equation (b) Thus

\mathrm{K}_3=\mathrm{K}_1 \cdot \mathrm{K}_2