An amount of solid NH_4 HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 ~atm . Pressure. Ammonium hydrogen sulphide decomposes to yield NH_3 and H_2 ~S gases in the flask. When

Correct answer: D. 0.11 Total pressure =0.5+2 x=0.84 i.e., x=0.17 ~K_ p =p_ NH_3 · p_ H_2 ~s =(0.67) .(0.17) =0.1139 .

JEE Main 2005

Exam: JEE Main
Year: 2005
Subject: Chemistry
Chapter: Chemical Equilibrium

JEE Main 2005 · Chemistry · Chemical Equilibrium

An amount of solid NH_4 HS is placed in a flask already containing...

An amount of solid

\mathrm{NH}_4 \mathrm{HS}

is placed in a flask already containing ammonia gas at a certain temperature and

0.50 \mathrm{~atm}

. Pressure. Ammonium hydrogen sulphide decomposes to yield

\mathrm{NH}_3

and

\mathrm{H}_2 \mathrm{~S}

gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to

0.84 \mathrm{~atm}

. The equilibrium constant for

\mathrm{NH}_4 \mathrm{HS}

decomposition at this temperature is An amount of solid NH_4 HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 ~atm .

An amount of solid NH_4 HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 ~atm .

Options

A $0.30$
B $0.18$
C $0.17$
D $0.11$

Correct answer

D. $0.11$

Step-by-step solution

Total pressure

=0.5+2 \mathrm{x}=0.84

i.e.,

\mathrm{x}=0.17

\mathrm{~K}_{\mathrm{p}}=\mathrm{p}_{\mathrm{NH}_3} \cdot \mathrm{p}_{\mathrm{H}_2 \mathrm{~s}}

=(0.67) .(0.17)

\quad=0.1139

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