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JEE Main 2004
Exam
JEE Main
Year
2004
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2004 · Chemistry · Chemical Equilibrium

What is the equilibrium expression for the reaction P_ 4(~s) +5 O_...

What is the equilibrium expression for the reaction P4( s)+5O2( g)⇌P4O10( s\mathrm{P}_{4(\mathrm{~s})}+5 \mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons \mathrm{P}_4 \mathrm{O}_{10(\mathrm{~s}} ?

Options

  1. AKc=[P4O10]/P4][O2]5\left.\mathrm{Kc}=\left[\mathrm{P}_4 \mathrm{O}_{10}\right] / \mathrm{P}_4\right]\left[\mathrm{O}_2\right]^5
  2. BKc=1/[O2]5\mathrm{Kc}=1 /\left[\mathrm{O}_2\right]^5
  3. CKc=[O2]5\mathrm{Kc}=\left[\mathrm{O}_2\right]^5
  4. DKc=[P4O10]/5[P4][O2]\mathrm{Kc}=\left[\mathrm{P}_4 \mathrm{O}_{10}\right] / 5\left[\mathrm{P}_4\right]\left[\mathrm{O}_2\right]

Correct answer

B. Kc=1/[O2]5\mathrm{Kc}=1 /\left[\mathrm{O}_2\right]^5

Step-by-step solution

Applying law of mass action
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