Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202628 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2026 · 28 January · Morning Shift · Chemistry · Electrochemistry

Consider the following redox reaction taking place in acidic medium...

Consider the following redox reaction taking place in acidic medium BH4−(aq)+ClO3−(aq)⟶H2BO3−(aq)+Cl−(aq)\mathrm{BH}_{4}^{-}(a q)+\mathrm{ClO}_{3}^{-}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{BO}_{3}^{-}(a q)+\mathrm{Cl}^{-}(a q) If the Nernst equation for the above balanced reaction is \mathrm{E}_{\text{cell }}=\mathrm{E}_{\text{cell }^{\circ}-\frac{\mathrm{RT}}{\mathrm{nF}} \ln \mathrm{Q} , then the value ofnisis\_\_\_\_.(Nearestinteger). (Nearest integer)

Correct answer

0

Step-by-step solution

3BH4−+4ClO3−⟶4Cl−+3H2BO3−+3H2O3BH_4^- + 4ClO_3^- \longrightarrow 4Cl^- + 3H_2BO_3^- + 3H_2O
n-factor =8= 8
moles =3= 3
∴n=3×8=24\therefore n = 3 \times 8 = 24
Practice Electrochemistry on Quantrex Academy →

More from Electrochemistry

At 300 K, the molar conductivities of the aqueous solutions of three salts at two… JEE Advanced 2026Given at 298 K: E^ _ Fe^ 2+ /Fe = X Volt; E^ _ Fe^ 3+ /Fe = Y Volt. The E^ _ Fe^ 3+ /Fe^… JEE Main 2026For a general redox reaction Anode : Red_1 arrow Ox_1^ n_1^+ + n_1 e^- Cathode : Ox_2 +… JEE Main 2026Consider the following data. Electrolyte Λ^ ∘ _m (S cm ^2 mol ^ -1 ) BaCl_2 x_1 H_2SO_4… JEE Main 2026One half cell in a voltaic cell is constructed by dipping silver rod in AgNO_3 solution… JEE Main 2026At 298 K , the molar conductivity of x\% (w/w) MX solution (aqueous) is 123.5 S cm^2 mol^… JEE Main 2026An electrochemical cell, consist of the following two redox couples, M^ x+ (aq)/M(s) [E_… JEE Main 2026Consider the following two half-cell reactions along with the standard reduction… JEE Main 2026 Full Electrochemistry list All JEE Main PYQs