JEE Main20253 Apr 2025Evening ShiftChemistryElectrochemistryActual
40 mL of a mixture of CH ₃ COOH and HCl (aqueous solution) is titrated against 0.1 M NaOH solution conductometrically. Which of the following statement is correct?
Options
- AThe concentration of CH ₃ COOH in the original mixture is 0.005 M
- BThe concentration of HCl in the original mixture is 0.005 M
- CCH ₃ COOH is neutralised first followed by neutralisation of HCl
- DPoint ' C ' indicates the complete neutralisation HCl
Correct answer
B. The concentration of HCl in the original mixture is 0.005 M
Step-by-step solution
From the given graph 2 ml NaOH solution is used for neutralisation of HCl and 3 ml NaOH solution is used for neutralisation of CH ₃ COOH . Mole of HCl = Mole of NaOH used aligned & M 40=0.1 2 & M =0.005 aligned Mole of CH ₃ COOH = Mole of NaOaH used aligned & M 40=0.1 3 & M =0.0075 aligned HCl is strong acid and will be neutralised first.