0.2 %( w / v ) solution of NaOH is measured to have resistivity 870.0 ~m ~m . The molar conductivity of the solution will be ______ 10^2 mS dm ^2 ~mol ⁻¹ . (Nearest integer)

Step-by-step solution

Given : Concentration of NaOH =0.2 %( w / v ) 0.2 ~g of NaOH in 100 ml of solution. Molarity of NaOH solution array r = moles of solute V _ ml 1000 = 0.2 / 40 100 1000== 0.2 40 100 1000= 2 40 M array Given resistivity of solution =870 ~m ohm m =870 10⁻³ ohm m =870 10⁻³ 10 ohm dm =870 10⁻² ohm dm =8.7 ohm dm Now conductivity K = 1 = 1 8.7 ohm ⁻¹ dm ⁻¹ Now molar conductivity of solution is aligned & _ m = K M = 1 8.7 2 40 = 40 2 8.7 =2.29 ~S dm ^2 ~mol ⁻¹ & 2.29 10^3 ~m ~S dm ^2 ~mol ⁻¹ & =22.9 10^2 ~m ~S dm ^2 ~mol