Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12 . The current in Amperes used for the given electrolysis is ____. (Nearest integer).

Step-by-step solution

Electrolysis of NaCl is NaCl + H ₂ O ( aq ) NaOH ( aq )+ 1 2 Cl ₂( ~g )+ 1 2 H ₂( ~g ) Since during electrolysis pH changes to 12 So [ OH ^ ]=10⁻² and [ H ⁺ ]=10⁻¹² So by Faraday law Gram amount of substance deposited = Amount of electricity passed aligned & 10⁻² 600 1000 96500= I t & 10⁻² 600 1000 96500= I 5 60 & I = 10⁻² 600 96500 1000 5 60 & I =1.93 ampere & So , I=2 ampere (nearest integer) aligned