JEE Main202523 Jan 2025Morning ShiftChemistryElectrochemistryActual
FeO ₄²⁻ +2.0 v Fe ³⁺ 0.8 v Fe ²⁺ -0.5 v Fe ^0 In the above diagram, the standard electrode potentials are given in volts (over the arrow). The value of E _ FeO ₄²⁻ / Fe ²⁺ ^ O is
Options
- A2.1 V
- B1 .7 V
- C1 .4 V
- D1 .2 V
Correct answer
B. 1 .7 V
Step-by-step solution
aligned & G ₄^ o = G ₁^ o + G ₂^ o & - n ₄ FE ₄^ o =- n ₁ FE ₁^0- n ₂ FE ₂^ o & +4 E ₄^ o =3 2+(1 0.8) & E ₄^ o = 6.8 4 ~V & E ₄^ o =1.7 ~V aligned