JEE Main 20245 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 5 April
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Electrochemistry
JEE Main 2024 · 5 April · Evening Shift · Chemistry · Electrochemistry
For the electro chemical cell ( gathered If E_ (M^ 2+ / M) ^0=0.46...
For the electro chemical cell
(\begin{gathered}
\text{ If } \mathrm{E}_{\left(\mathrm{M}^{2+} / \mathrm{M}\right)}^0=0.46 \mathrm{ V} \text{ and } \mathrm{E}_{\left(\mathrm{x} / \mathrm{X}^{2-}\right)}^0=0.34 \mathrm{ V} \text{. }
\end{gathered})
Which of the following is correct?
Options
- A(\mathrm{M}+\mathrm{X} \rightarrow \mathrm{M}^{2+}+\mathrm{X}^{2-}) is a spontaneous reaction
- B(\mathrm{E}_{\text{cell }}=0.80 \mathrm{ V})
- C(\mathrm{E}_{\text{cell }}=-0.80 \mathrm{ V})
- D(\mathrm{M}^{2+}+\mathrm{X}^{2-} \rightarrow \mathrm{M}+\mathrm{X}) is a spontaneous reaction
Correct answer
D. (\mathrm{M}^{2+}+\mathrm{X}^{2-} \rightarrow \mathrm{M}+\mathrm{X}) is a spontaneous reaction
Step-by-step solution
\begin{aligned}
& \mathrm{M} \mid \mathrm{M}^{+2} \| \mathrm{X} / \mathrm{X}^{2-} \\
& \mathrm{E}_{\mathrm{cell}^{\mathrm{o}}=\mathrm{E}_{\mathrm{M} / \mathrm{M}^{+2}}^{\mathrm{o}}+\mathrm{E}_{\mathrm{X} / \mathrm{X}^{-2}}^{\mathrm{o}} \\
& =-0.46+0.34=-0.12 \mathrm{ V}
\end{aligned}As \mathrm{E}_{\text{cell }^{\mathrm{o}} is negative so anode becomes cathode and cathode become anode. Spontaneous reaction will be