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JEE Main 20244 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
4 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2024 · 4 April · Evening Shift · Chemistry · Electrochemistry

For a strong electrolyte, a plot of molar conductivity against...

For a strong electrolyte, a plot of molar conductivity against (concentration) 1/2{ }^{1 / 2} is a straight line, with a negative slope, the correct unit for the slope is

Options

  1. A(\mathrm{S} \mathrm{cm}{ }^2 \mathrm{~mol}^{-3 / 2} \mathrm{~L}^{-1 / 2})
  2. B(\mathrm{S} \mathrm{cm}^2 \mathrm{~mol}^{-3 / 2} \mathrm{~L}^{1 / 2})
  3. C(\mathrm{S} \mathrm{cm}^2 \mathrm{~mol}^{-3 / 2} \mathrm{~L})
  4. D(\mathrm{S} \mathrm{cm}^2 \mathrm{~mol}^{-1} \mathrm{~L}^{1 / 2})

Correct answer

B. (\mathrm{S} \mathrm{cm}^2 \mathrm{~mol}^{-3 / 2} \mathrm{~L}^{1 / 2})

Step-by-step solution

Λm=Λm∘−AC\Lambda_{\mathrm{m}}=\Lambda_{\mathrm{m}}^{\circ}-\mathrm{A} \sqrt{\mathrm{C}}
Units of AC=Scm2 mole−1\mathrm{A} \sqrt{\mathrm{C}}=\mathrm{S} \mathrm{cm}^2 \mathrm{~mole}^{-1} Uits of A=Scm2 mole−3/2 L1/2\mathrm{A}=\mathrm{S} \mathrm{cm}^2 \mathrm{~mole}^{-3 / 2} \mathrm{~L}^{1 / 2}
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