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The reaction occurs in which of the given galvanic cell? 1 2 H 2 ( g ) + AgCl ( s ) ⇌ H + ( aq ) + Cl - ( aq ) + Ag ( s )

Options

  1. APt | H 2 ( g ) | HCl ( sol n   ) | AgCl ( s ) | Ag
  2. BAg | AgCl ( s ) | KCl ( sol n   ) | AgNO 3 | Ag
  3. CPt | H 2 ( g ) | HCl ( sol n   ) | AgNO 3 ( sol n   ) | Ag
  4. DPt | H 2 ( g ) | KCl ( sol n   ) | AgCl ( s ) | Ag

Correct answer

A. Pt | H 2 ( g ) | HCl ( sol n   ) | AgCl ( s ) | Ag

Step-by-step solution

Oxidation is loss of electron and in a galvanic cell it occurs at anode. Reduction is gain of electron and in a galvanic cell it occurs at cathode. At anode : 1 2 H 2 (   g ) ⟶ H + ( aq ) + e - At cathode AgCl ( S ) + e ¯ ⟶ Ag + Cl -  (aq)  Overall reaction 1 2 H 2 (   g ) + AgCl ( s ) ⟶ H * + Cl - + Ag ( s ) Cell representation : Anode / Anode electrolyte || Cathodic electrolyte / Cathode. The cell representation for the above cell will be Pt H 2 (   g ) HCl &#160

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