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JEE Main 20236 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
6 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2023 · 6 April · Evening Shift · Chemistry · Electrochemistry

The standard reduction potentials at 295K for the following half...

The standard reduction potentials at 295K295K for the following half cells are given below:

NO3−+4H++3e−→NO(g)+2H2O{{NO}_{3}}^{-} + 4{H}^{+} + 3{e}^{-} \to NO\left(g\right) + 2{H}_{2}O Eo=0.97V{E}^{o} = 0 . 97V
V2+(aq)+2e−→V(s){V}^{2 +}\left(aq\right) + 2{e}^{-} \to V\left(s\right) Eo=−1.19V{E}^{o} = - 1 . 19V
Fe3+(aq)+3e−→Fe(s){Fe}^{3 +}\left(aq\right) + 3{e}^{-} \to Fe\left(s\right) Eo=−0.04V{E}^{o} = - 0 . 04V
Ag+(aq)+e−→Ag(s){Ag}^{+}\left(aq\right) + {e}^{-} \to Ag\left(s\right) Eo=0.80V{E}^{o} = 0 . 80V
Au3+(aq)+3e−→Au(s){Au}^{3 +}\left(aq\right) + 3{e}^{-} \to Au\left(s\right) Eo=1.40V{E}^{o} = 1 . 40V

The number of metal(s) which will be oxidised by NO3−{{NO}_{3}}^{-} in aqueous solution is _____.

Correct answer

0

Step-by-step solution

For feasibility, check , Eocell=Ecathode(reduction)o−Eanode(oxidation)o>0{E}^{o}cell = {E}_{cathode ( reduction )}^{o} - {E}_{anode ( oxidation )}^{o} > 0

The Eo{E}^{o} values when metal acts as anode and NO3−{NO}_{3}^{-} reaction is cathodic reaction.

For Vanadium metal, Ecello=0.97+1.19=2.16V{E}_{cell}^{o} = 0 . 97 + 1 . 19 = 2 . 16V

For Iron metal, Ecello=0.97+0.04=1.01V{E}_{cell}^{o} = 0 . 97 + 0 . 04 = 1 . 01V

For silver metal, Ecello=0.97−0.80=0.17V{E}_{cell}^{o} = 0 . 97 - 0 . 80 = 0 . 17V

For Gold metal, Ecello=0.97−1.140=−0.17V{E}_{cell}^{o} = 0 . 97 - 1 . 140 = - 0 . 17V

For electrodes having oxidation potential greater than −0.97V- 0 . 97V, Eocell>0{E}^{o}cell > 0

∴Ag,Fe∴ Ag, Fe and VV can be oxidised

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