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JEE Main 202329 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
29 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2023 · 29 January · Morning Shift · Chemistry · Electrochemistry

The standard electrode potential ( M ^ 3 + / M ^ 2 + ) for V, Cr,...

The standard electrode potential (M3+/M2+{M}^{3 +} / {M}^{2 +}) for V,Cr,MnV, Cr, Mn & CoCo are −0.26V,−0.41V,+1.57V- 0 . 26V, - 0 . 41V, + 1 . 57V and +1.97V+ 1 . 97V, respectively. The metal ions which can liberate H2{H}_{2} from a dilute acid are

Options

  1. AV2+{V}^{2 +} and Mn2+{Mn}^{2 +}
  2. BCr2+{Cr}^{2 +} and Co2+{Co}^{2 +}
  3. CV2+{V}^{2 +} and Cr2+{Cr}^{2 +}
  4. DMn2+{Mn}^{2 +} and Co2+{Co}^{2 +}

Correct answer

C. V2+{V}^{2 +} and Cr2+{Cr}^{2 +}

Step-by-step solution

The E⊝{E}^{⊝} values for the redox couple (M3+/M2+{M}^{3 +} / {M}^{2 +}) shows that Mn2+{Mn}^{2 +} and Co2+{Co}^{2 +} ions are the strongest oxidising agents in aqueous solution.

The ions Ti2+,V2+andCr2+{Ti}^{2 +}, {V}^{2 +}and{Cr}^{2 +} are strong reducing agents and will liberate hydrogen from a dilute acid.

So, the Correct answer is V2+andCr2+{V}^{2 +}and{Cr}^{2 +}.

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