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JEE Main 202225 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
25 July
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2022 · 25 July · Evening Shift · Chemistry · Electrochemistry

The molar conductivity of a conductivity cell filled with 10 moles...

The molar conductivity of a conductivity cell filled with 1010 moles of 20mLNaCl20mLNaCl solution is Λm1{Λ}_{m1} and that of 2020 moles another identical cell heaving 80mLNaCl80mLNaCl solution is Λm2{Λ}_{m2}, The conductivities exhibited by these two cells are same.

The relationship between Λm2{Λ}_{m2} and Λm1{Λ}_{m1} is

Options

  1. AΛm2=2Λm1{Λ}_{m2} = 2{Λ}_{m1}
  2. BΛm2=Λm1/2{Λ}_{m2} = {Λ}_{m1} / 2
  3. CΛm2=Λm1{Λ}_{m2} = {Λ}_{m1}
  4. DΛm2=4Λm1{Λ}_{m2} = 4{Λ}_{m1}

Correct answer

A. Λm2=2Λm1{Λ}_{m2} = 2{Λ}_{m1}

Step-by-step solution

Λm=κ×1000M{Λ}_{m} = κ \times \dfrac{1000}{M}

⇒Λm∝1M⇒ {Λ}_{m} ∝ \dfrac{1}{M}

Λm1Λm2=M2M1=20801020=14×21=12\dfrac{{Λ}_{m1}}{{Λ}_{m2}} = \dfrac{{M}_{2}}{{M}_{1}} = \dfrac{\dfrac{20}{80}}{\dfrac{10}{20}} = \dfrac{1}{4} \times \dfrac{2}{1} = \dfrac{1}{2}

⇒Λm2=2Λm1⇒ {Λ}_{m2} = 2{Λ}_{m1}

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