The solubility product of a sparingly soluble salt A 2 X 3 is 1 . 1 × 10 - 23 . If specific conductance of the solution is 3 × 10 - 5 Sm - 1 , the limiting molar conductivity of the solution is x × 10 - 3 S m 2 mol - 1 . The value of x is

Step-by-step solution

K sp A 2 X 3 = 1 . 1 × 10 - 23 = 110 × 10 - 25 K sp = 2 2 3 3 s 5 = 110 × 10 - 25 4 × 27 s 5 = 110 × 10 - 25 ;    S = M = 1 × 10 - 5 K = 3 × 10 - 5 Sm - 1 λ m = x × 10 - 3 Sm 2   mol - 1 λ m = K × 10 - 3 M = 3 × 10 - 5 × 10 - 3 1 × 10 - 5 = 3 × 10 - 3 Sm 2   mol - 1