JEE Main202224 Jun 2022Evening ShiftChemistryElectrochemistryActual
The resistance of a conductivity cell containing 0 . 01   MKCl solution at 298   K is 1750   Ω . If the conductivity of 0 . 01   MKCl solution at 298   K is 0 . 152 × 10 - 3   S   cm - 1 , then the cell constant of the conductivity cell is____ × 10 - 3   cm - 1
Correct answer
0
Step-by-step solution
For KCl solution, R = 1750 ohms Conductivity, K = 0 . 152 × 10 - 3   S   cm - 1 K= l a 1 R Cell constant, l a = K   XR = 0 . 152 × 10 - 3     X   1750 = 266 X 10 - 3 cm - 1