JEE Main202126 Aug 2021Evening ShiftChemistryElectrochemistryActual
For the galvanic cell, Zn ( s ) + Cu 2 + ( 0 . 02 M ) → Zn 2 + ( 0 . 04 M ) + Cu ( s ) E cell = … × 10 - 2 V (Nearest integer) Use : E 0 Cu / Cu 2 + = - 0 . 34 V , E Zn / Zn 2 + = + 0 . 76 V , 2 . 303 RT F = 0 . 059 V
Correct answer
0
Step-by-step solution
Cell reaction Cu 2 + ( aq ) + Zn ⇌ Cu ( s ) + Zn 2 + ( aq ) 0 . 02 M                                                               0 . 04 M E c e l l 0 = E C u 2 + ∣ C u 0 - E Z n 2 + ∣ Z n 0 = 0 . 34 - ( - 0 . 75 ) = 1 . 1   V E cell = E cell 0 - 0 . 059 2 log Zn 2 + Cu 2 + = 1 . 1 - 0 . 059 2 log 0 . 04 0 . 02 = 1 . 1 - 0 . 03 log 2 = 1 .