For the galvanic cell, Zn ( s ) + Cu ^ 2 + ( 0 . 02M ) → Zn ^ 2 + (...

Cell reaction

${Cu}^{2 +} ( aq ) + Zn ⇌ Cu ( s ) + {Zn}^{2 +} ( aq )$

$0 . 02M0 . 04M$

{E}_{cell}^{0} = {E}_{C{u}^{2 +} ∣ Cu}^{0} - {E}_{Z{n}^{2 +} ∣ Zn}^{0}]$</p><p>$= 0 . 34 - ( - 0 . 75 ) = 1 . 1V$</p><p>${E}_{cell} = {E}_{cell}^{0} - \dfrac{0 . 059}{2}log\dfrac{\left[{Zn}^{2 +}\right]}{\left[{Cu}^{2 +}\right]}$</p><p>$= 1 . 1 - \dfrac{0 . 059}{2}\log \left(\dfrac{0 . 04}{0 . 02}\right)$</p><p>$= 1 . 1 - 0 . 03\log 2 = 1 . 1 - 0 . 03 \times 0 . 30$</p><p>$= 1 . 0915 = 1 . 09V = 109 \times {10}^{- 2}V