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The conductivity of a weak acid   HA of concentration 0 . 001   mol   L - 1 is 2 . 0 × 10 - 5   S   cm - 1 . If Λ m 0 ( HA ) = 190   S   cm 2   mol - 1 , the ionization constant K a of HA is equal to _ _ _ _ × 10 - 6 (Round off to the Nearest Integer)

Correct answer

0

Step-by-step solution

Λ m = 1000 × K M = 1000 × 2 × 10 - 5 0 . 001 = 20   S   cm 2   mol - 1 ⇒ α = Λ m Λ m ∞ = 20 190 = 2 19 = 12 . 3 × 10 - 6

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