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JEE Main 202122 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
22 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2021 · 22 July · Morning Shift · Chemistry · Electrochemistry

Assume a cell with the following reaction Cu _ ( s ) + 2 Ag ^ + (1...

Assume a cell with the following reaction Cu(s)+2Ag+(1×10−3M)→Cu2+(0.250M)+2Ag(s){Cu}_{( s )} + 2{Ag}^{+}\left(1 \times {10}^{- 3}M\right) \to {Cu}^{2 +} ( 0 . 250M ) + 2{Ag}_{( s )}
Ecell∘=2.97V{E}_{cell}^{∘} = 2 . 97V

Ecell{E}_{cell} for the above reaction is V.V .

(Nearest integer)

[[ Given : log⁡2.5=0.3979,T=298K]\log 2 . 5 = 0 . 3979, T = 298K ]

Correct answer

0

Step-by-step solution

E=E°−0.0592log[Cu+2][Ag+]2E = E ° - \dfrac{0 . 059}{2}log\dfrac{\left[{Cu}^{+ 2}\right]}{{\left[{Ag}^{+}\right]}^{2}}
=2.97−0.0592log0.25(10−3)2=2.81V= 2 . 97 - \dfrac{0 . 059}{2}log\dfrac{0 . 25}{{\left({10}^{- 3}\right)}^{2}} = 2 . 81V
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