Emf of the following cell at 298K in V is x × 10 ^ - 2 Zn| Zn ^ 2 +...

${E}_{cell}^{0} = {E}_{{Ag}^{+} / Ag}^{0} - {E}_{{Zn}^{2 +} / Zn}^{0}$

$= 0 . 80 - \left(- 0 . 76\right)$

$= 1 . 56V$

${E}_{cell} = 1 . 56 - \dfrac{0 . 059}{2}log\dfrac{\left[{Zn}^{2 +}\right]}{{\left[{Ag}^{+}\right]}^{2}}$

$= 1 . 56 - \dfrac{0 . 059}{2}log\dfrac{0 . 1}{{\left(0 . 01\right)}^{2}}$

$= 1 . 56 - \dfrac{0 . 059}{2} \times 3$

$= 1 . 56 - 0 . 0885$

$= 1 . 4715$

$= 147 . 15 \times {10}^{- 2}$