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Emf of the following cell at 298 K in V is x × 10 - 2 Zn Zn 2 + 0 . 1 M ‖ Ag + 0 . 01 M Ag The value of x is ________________ (Rounded off to the nearest integer) Given : E Zn 2 + / Zn θ = - 0 . 76 V ; E Ag + / Ag θ = + 0 . 80 V ; 2 . 303 RT F = 0 . 059

Correct answer

0

Step-by-step solution

E cell 0 = E Ag + / Ag 0 - E Zn 2 + / Zn 0 = 0 . 80 - - 0 . 76 = 1 . 56   V E cell = 1 . 56 - 0 . 059 2 log Zn 2 + Ag + 2 = 1 . 56 - 0 . 059 2 log 0 . 1 0 . 01 2 = 1 . 56 - 0 . 059 2 × 3 = 1 . 56 - 0 . 0885 = 1 . 4715 = 147 . 15 × 10 - 2

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