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JEE Main 20206 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2020 · 6 September · Evening Shift · Chemistry · Electrochemistry

For the given cell; Cu(s) | Cu ^ 2 + ( C _ 1 M) || Cu ^ 2 + ( C _ 2...

For the given cell; Cu(s)Cu\left(s\right)\left|{Cu}^{2 +}\left({C}_{1}M\right)\right|\left|{Cu}^{2 +}\left({C}_{2}M\right)\right|Cu\left(s\right)</p><p>change in Gibbsenergy(∆G)isnegative,it:Gibbs energy \left(∆ G\right) is negative, it :

Options

  1. AC1=C2{C}_{1} = {C}_{2}
  2. BC2=C12{C}_{2} = \dfrac{{C}_{1}}{\sqrt{2}}
  3. CC1=2C2{C}_{1} = 2{C}_{2}
  4. DC2=2C1{C}_{2} = \sqrt{2}{C}_{1}

Correct answer

D. C2=2C1{C}_{2} = \sqrt{2}{C}_{1}

Step-by-step solution

For concentration cell Ecello¯=0Ecell\mathop{o}_{¯} = 0

Anode : Cu(s)→Cu2+(aq)ACu\left(s\right) \to {Cu}^{2 +}\left(aq\right)A

Cathode : Cu2+(aq)c→Cu(s){Cu}^{2 +}\left(aq\right)c \to Cu\left(s\right)

Overall : Cu2+(aq)c→Cu2+(aq)¯A\overset{¯}{{Cu}^{2 +}\left(aq\right)c \to {Cu}^{2 +}\left(aq\right)}A

As ΔG=−nFEcell\Delta G = - nF{E}_{cell}

If ΔG=−ve\Delta G = - ve then Ecell{E}_{cell} is positive.

Ecell=Ecello¯−0.0592logC1C2{E}_{cell} = Ecell\mathop{o}_{¯} - \dfrac{0 .059}{2}log\dfrac{{C}_{1}}{C2}

Ecell=−0.0592logC1C2{E}_{cell} = \dfrac{- 0 .059}{2}log\dfrac{{C}_{1}}{C2}

Ecell>0{E}_{cell} > 0

⇒⇒ C2>C1{C}_{2} > {C}_{1}

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