250 mL of a waste solution obtained from the workshop of a goldsmith contains 0 . 1 M AgNO 3 and 0 . 1 M AuCl . The solution was electrolyzed at 2 V by passing a current of 1 A for 15 minutes. The metal/metals electrodeposited will be : E Ag + / Ag 0 = 0 . 80 V , E Au + / Au 0 = 1 . 69 V

Step-by-step solution

 Charge  ( q ) =  it  96500 F = 1 × 15 × 60 96500 = 900 96500 = 9 965 F = 0 . 0093   F No. of moles of Au + = 0 . 025 & No. of moles of Ag + = 0 . 025 Species with higher value of SRP will get deposited first at cathode. ( i )   Au + ( aqs )   +   e - ⟶   Au ( s ) 0 . 025                     0 . 0093 mole so only Au will get deposited.