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Two Faraday of electricity is passed through a solution of C u S O 4 . The mass of copper deposited at the cathode is: (Atomic mass of Cu = 63.5 amu)

Options

  1. A127 g
  2. B0   g
  3. C63.5 g
  4. D2 g

Correct answer

C. 63.5 g

Step-by-step solution

Cu + 2   +   2 e -   →   Cu 2 Faraday charge deposits 1 mol of Cu, or 2   F ≡ 2   Equivalents   of   Cu Mass of Cu deposited = 2 × 63 .5 2 = 63 .5 g

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