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Given Fe ³⁺( aq )+ e ⁻ Fe ²⁺( aq ) ; E ^0=+0.77 ~V aligned & Al ³⁺( aq )+3 e ⁻ Al ( s ) ; E ^0=-1.66 ~V & Br ₂( aq )+2 e ⁻ 2 Br ⁻ ; E ^0=+1.09 ~V aligned Considering the electrode potentials, which of the following represents the correct order of reducing power?

Options

  1. AFe ²⁺ < A l < Br ⁻
  2. BBr ⁻ < Fe ²⁺ < Al
  3. CAl < Br ⁻ < Fe ²⁺
  4. DAl < Fe ²⁺ < Br ⁻

Correct answer

D. Al < Fe ²⁺ < Br ⁻

Step-by-step solution

Reducing character decreases down the series. Hence the correct order is Al < Fe ²⁺ < Br ⁻

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