JEE Main2013ChemistryElectrochemistryActual
Electrode potentials ( E ^ ) are given below : aligned & Cu ⁺ / Cu =+0.52 ~V , & Fe ³⁺ / Fe ²⁺=+0.77 ~V , & 1 2 I ₂( ~s ) / I ⁻=+0.54 ~V , & Ag ⁺ / Ag =+0.88 ~V . aligned Based on the above potentials, strongest oxidizing agent will be :
Options
- ACu ⁺
- BFe ³⁺
- CAg ⁺
- DI ₂
Correct answer
C. Ag ⁺
Step-by-step solution
Higher the value of reduction potential stronger will be the oxidising hence based on the given values Ag ⁺ will be strongest oxidizing agent.