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The equivalent conductances of two strong electrolytes at infinite dilution in H ₂ O (where ions move freely through a solution) at 25^ C are given below: ^ CH ₃ COONa =91.0 ~S ~cm ^2 /equiv _ HCl ^ =426.2 ~S ~cm^2 / equiv What additional information/quantity one needs to calculate ^ of an aqueous solution of acetic acid?

Options

  1. A^ of NaCl
  2. B^ of CH ₃ COOK
  3. CThe limiting equivalent conductance of H ⁺ ( _ H ⁺ ^ )
  4. D^ of chloroacetic acid ( C / CH ₂ COOH )

Correct answer

A. ^ of NaCl

Step-by-step solution

From Kohlrausch's law _ CH ₃ COOH ^ = _ CH ₃ COONa ^ + _ HCl ^ - _ NaCl ^ Hence, (A) is the correct answer.

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