JEE Main2003ChemistryElectrochemistryActual
For a cell reaction involving a two-electron change, the standard e.m.f. of the cell is found to be 0.295 ~V at 25^ C . The equilibrium constant of the reaction at 25^ C will be
Options
- A29.5 10⁻²
- B10
- C1 10¹⁰
- D1 10⁻¹⁰
Correct answer
D. 1 10⁻¹⁰
Step-by-step solution
The equilibrium constant is related to the standard emf of cell by the expression K=E_ cell ^0 n 0.059 =0.295 2 0.059 K = 590 59 =10 or K =1 10⁻¹⁰