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When during electrolysis of a solution of AgNO ₃ 9650 coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be

Options

  1. A10.8 ~g
  2. B21.6 ~g
  3. C108 ~g
  4. D1.08 ~g

Correct answer

A. 10.8 ~g

Step-by-step solution

No. of moles of silver = 9650 96500 = 1 10 moles Mass of silver deposited = 1 10 108=10.8 ~g

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