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JEE Main2002ChemistryElectrochemistryActual

EMF of a cell in terms of reduction potential of its left and right electrodes is

Options

  1. AE=E_ left -E_ right
  2. BE=E_ left +E_ right
  3. CE=E_ right -E_ left
  4. DE=- (E_ right +E_ left )

Correct answer

C. E=E_ right -E_ left

Step-by-step solution

aligned E _ cell & = Reduction potential of cathode (right) - reduction potential of anode (left) & = E _ right - E _ left aligned

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