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Which of the following statements support the cyclic form for glucose? (i) It doesn't give Schiff's test. (ii) It is found to exist in two different crystalline forms. iii) It oxidises with nitric acid to give saccharic acid. (iv) Pentaacetate of glucose doesn't react with hydroxylamine.

Options

  1. A(i), (ii) and (iv)
  2. B(i), (iii) and (iv)
  3. C(ii) and (iii)
  4. D(i), (ii) and (iii)

Correct answer

A. (i), (ii) and (iv)

Step-by-step solution

(ii) Anomeric crystalline form (i) do not give Schiff's test, because, - CHO group is not free. (iv) Pentaacetate do not react with hydroxylamine, because C = O is not available. So, statements (i), (ii) and (iv) support the cyclic structure of glucose.

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