99 Percentile Qs Bank for JEE MainChemistryElectrochemistry
Calculate the equilibrium constant of the reaction, Cu (s)+2 Ag ⁺(a q) Cu ²⁺(a q)+2 Ag (s) , given that for the reaction E_ cell =0.46 ~V .
Options
- A4.2 10^8
- B6.23 10^9
- C3.92 10¹⁵
- D4.54 10²⁰
Correct answer
C. 3.92 10¹⁵
Step-by-step solution
aligned G^ & =-n F E_ cell ^ G^ & =-2.303 R T K K & = n F E_ cell ^ 2303 R T = 2 96500 0.46 2.303 8.31 298 =15.56 K & =15.56 K=3.92 10¹⁵ aligned Hence, the correct option is (3).