99 Percentile Qs Bank for JEE MainChemistryElectrochemistry
If the resistance of 0.1 M KCl solution in a conductance cell is 300 and conductivity is 0.013 Scm ⁻¹ , then the value of cell constant is
Options
- A3.9 ~cm ⁻¹
- B39 ~m ⁻¹
- C3.9 ~m ⁻¹
- D0.39 ~cm ⁻¹
Correct answer
A. 3.9 ~cm ⁻¹
Step-by-step solution
Conductivity ( )= 1 Resistance (R) cell constant Cell constant = R Given, =0.0135 ~cm ⁻¹ R=300 Cell constant =0.0135 300=3.9 ~cm ⁻¹ .