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E ^ cell is 1 049 ~V and involves transfer of 2 electrons, calculate equilibrium constant of cell?

Options

  1. A2.75 10³⁵
  2. B2.75 10¹⁰
  3. C0 524 10³⁵
  4. D2 098 10¹⁰

Correct answer

A. 2.75 10³⁵

Step-by-step solution

E _ cell ⁰=1.049 ~V , n =2, ~K =? E _ cell ⁰= 0.0592 n ₁₀ ~K ₁₀ ~K = E _ cell ⁰ n 0.0592 = 1.049 2 0.0592 ₁₀ ~K =35.439 K = Antilog (35.439) K =2.75 10³⁵

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