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What is the time (in sec) required for depositing all the silver present in 125 ~mL of 1 M AgNO ₃ solution by passing a current of 241.25 ~A ? (1F =96500 coulombs )

Options

  1. A10
  2. B50
  3. C1000
  4. D100

Correct answer

B. 50

Step-by-step solution

Given 125 ~mL of 1 M AgNO ₃ solution. It means that 1000 ~mL of AgNO ₃ solution contains =108 ~g Ag 125 ~mL of AgNO ₃ solution contains = 108 125 1000 ~g Ag =13.5 ~g Ag 108 ~g of Ag is deposited by 96500 C 13.5 ~g of Ag is deposited by = 96500 108 13.5=12062.5 C Q=i tt= Q i = 12062.5 241.25 =50

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