99 Percentile Qs Bank for JEE MainChemistryElectrochemistry
The molar conductivity of 0.027 M methanoic acid is 40.42 Scm ^2 ~mol ⁻¹ . The value of dissociation constant of this acid is ( . Given _ H ⁺ ^ =349.6 ~S _ . , cm ^2 ~mol ⁻¹ and _ HCOO ⁻ ^ =54.6 ~S . cm ^2 ~mol ⁻¹ )
Options
- A1.5 10⁻⁵
- B6.0 10⁻⁵
- C4.5 10⁻⁴
- D3.0 10⁻⁴
Correct answer
D. 3.0 10⁻⁴
Step-by-step solution
aligned & _ m ^ o ( HCOOH )= _ H ⁺ ^0+ _ HCOO ⁻ ^0 & =349.6+54.6 & =404.2 ~S ~cm ^2 ~mol ⁻¹ & = _ m _ m ^0 = 40.42 404.2 =0.1 & k _ a = ^2 1- = 0.027(0.1)^2 1-0.1 & =0.0003=3.0 10⁻⁴ aligned