Find the observed EMF of the cell ( Cd | Cd ²⁺(0.01 M ) | Cd ²⁺(0.01 M ) | Cd ) under conditions, internal resistance of (4 ) and producing a current of (0.15 ~A ). (Given, (E^ Cu ²⁺ / Cu =0.35 ~V ) and ( E_ Cd ²⁺ / Cd ^ =-0.4 ~V ) )

Step-by-step solution

The cell representation is ( Cd / Cd ²⁺(0.01 M ) | Cu ²⁺(0.01 M ) Cu ) Note In the statement of the question, this portion is written as ( ^" Cd ²⁺(0.01 M ) Cd ) " which is wrong. The cell reaction is ( gathered Cd (s)+ (0.01 M ) Cu ²⁺ (0.01 M ) Cd ²⁺ + Cu (s) Q= [ Cd ²⁺ ][ Cu ] [ Cd ] [ Cu ²⁺ ] = 0.01 1 1 0.01 =1 gathered ) ( aligned E_ cell & = (E_ Cu ²⁺ / Cu ^ -E_ Cd ²⁺ / Cd ^ )- 0.0591 2 Q & =[0.35-(-0.40)]-0 [ Q= l =0] & =0.75 ~V E_ cell ^ obscrved & =E_ intemal -E_ extemal & =0.75-( resistance current ) & =0.