When electric current is passed through acidified water for 1930 ~s , 1120 ~mL of H ₂ gas is collected (at STP) at the cathode. What is the current passed in amperes?

Step-by-step solution

Electrolysis of water takes place as follows H ₂ O cathode H ⁺ + anode OH ⁻ At anode aligned & OH ⁻ Oxidation OH +e⁻ & 4 OH 2 H ₂ O + O ₂ aligned At cathode 2 H ⁺+2 e⁻ Reduction H ₂ Given, time, t=1930 ~s Number of moles of hydrogen collected aligned & = 1120 10⁻³ 22.4 moles & =0.05 moles aligned 1 mole of hydrogen is deposited by =2 moles of electrons 0.05 moles of hydrogen will be deposited by aligned & =2 0.05 & =0.10 mole of electrons aligned Charge, aligned Q & =n F & =0.1 96500 aligned Charge, Q=i t aligned 0